sec[arcsin(1404/1405)]的值？
更新时间：2021-12-31 11:36:33 • 作者：STEPHANIE •阅读 7626
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sec(arcsin(3/4))怎么解答
解：令arcsin(3/4)=α,
则，sinα=3/4.
cosα=√(1-sin^2α)=√7/4,
secα=1/cosα,
=1/(√7/4),
=4√7/7,
∴sec(arcsin(3/4)=4√7/7.
解：令arcsin(3/4)=α,
则，sinα=3/4.
cosα=√(1-sin^2α)=√7/4,
secα=1/cosα,
=1/(√7/4),
=4√7/7,
∴sec(arcsin(3/4)=4√7/7.