解方程3(x-2)=2-5(x-2) 要求写出解题过程(2x x-3 0)

解方程:(x - 5) 2 =2(x - 5

x 1 =5,x 2 =-7 .试题分析:先移项得 ,再提取公因式 ,可解此方程..试题解析:解:所以 =＂0＂ , =0 即x 1 =5,x 2 =-7

怎样解3(X - 5)2=2(5 - X)

3(x-5)^2=2(5-x)3(x-5)^2-2(5-x)=03(x-5)^2+2(x-5)=0(x-5)[3(x-5)+2]=0(x-5)(3x-13)=0x=5或x=13/3

3(X - 5)^2=2(5 - X)这个二元一次 要步骤和解法

3(X-5)^2 =2(5-X)3(X-5)^2= -2(X-5)3(X-5)^2+2(X-5)=0(X-5)[3(X-5)+2]=0(X-5)(3X-15+2)=0(X-5)(3X-13)=0X=5 or X=(13/3)

解方程 3x(x - 2)=2(2 - x) 怎么解的,详细过程,谢谢

∵|x+2|≥0, ∴-3x≥0, ∴x≤0, x+2=-3x, x =-1/2

3(x - 2) - 2(x - 2)=4 - 5x的解法 求步骤

3(x-2)-2(x-2)=4-5x x-2=4-5x6x=6 x=1

用初三的方法解一下 3(x - 5)²=2(5 - x) 要有具体过程 谢谢!

3(x-5)^2=2(5-x)3(5-x)^2=2(5-x)[3(5-x)-2](5-x)=0(13-3x)(5-x)=0x1=13/3,x2=5

用适当的方法解方程(x - 2)/2 - (5 - y)/3=1 ,x/0.2 - (y+1)/0.3=5

(x-2)/2-(5-y)/3=1 →【(x-2)/2-(5-y)/3】*6=1*6→3(X-2)-2(5-y)=6→3x+2y=22 0.2=1/5 ,0.3=3/10,原式→5x-10(y+1)/3=5→【5x-10(y+1)/3】*3=5*3→15x-10y=5解方程组就行了

解这个方程:3(x - 5)²=2(5 - x)

3(x-5)²=2(5-x)3(x-5)²+2(X-5)=0(x-5)(3x-15+2)=0(x-5)(3x-13)=0 x1=5,x2=13/3

解方程:2^x - 2^ - x/2^x+2 - x=3/5 要写过程

a=2^x2^-x=1/a(a-1/a)/(a+1/a)=3/5(a^2-1)/(a^2+1)=3/55a^2-5=3a^2+3a^2=4a=2^x>0则2^x=a=2x=1

方程X+3=2分之X - 5求解步骤

1 X+3=(X-5)/22(X+3)=X-52X+6=X-5X=-11 2 x+3=x/2-5 x/2=-8 x=-16