（二x-1）-3+7-2+8=x-1？ x的二次方减2x加1

• X-3/3-X-7/2=1等于多少
• x-1/2[x-1/2(x-1/2)]=8
• 3|x-1|-7=2怎么解
• 2/1[x-2/1(x-1)]=3/2(x-1)

X-3/3-X-7/2=1等于多少

X-3/3-X-7/2=1

乘以6得 2(x-3)-3(x-7)=6

2x-6-3x+21=6

2x-3x=6+6-21

-x=-9

x=9

x-1/2[x-1/2(x-1/2)]=8

x-1/2[x-1/2(x-1/2)]=8

x-1/2x+1/4x-1/8=8

8x-4x+2x-1=64

6x=65

x=65/6

3|x-1|-7=2怎么解

一3（x一1）=2你把它算好就0k了

2/1[x-2/1(x-1)]=3/2(x-1)

x＝7/5