怎样计算:(x-1)(x-2)(x-3)(x-4) 有啥简便方法? x+1 x+2 x+3 x+4
更新时间:2021-08-29 10:12:22 • 作者:RANDAL •阅读 7539
- (x-1)(x-2)(x-3)(x-4)怎么算,要用简便的方法来算
- (X-1)(X-2)(X-3)(X-4)=?简便方法
- (x-1)(x-2)(x-3)(x-4)-120 谁能告诉我过程的答案,化简的,
- y=(x-1)(x-2)^2(x-3)^3(x-4)^4求导
(x-1)(x-2)(x-3)(x-4)怎么算,要用简便的方法来算
(x-1)(x-2)(x-3)(x-4)
=[(x-1)(x-4)][(x-2)(x-3)]
=(x^2-5x+4)(x^2-5x+6)
=(x^2-5x)^2+10(x^2-5x)+24
=x^4-10x^3+25x^2+10x^2-50x+24
=x^4-10x^3+35x^2-50x+24
(X-1)(X-2)(X-3)(X-4)=?简便方法
(X-1)(X-2)(X-3)(X-4)
= [(x -1)(x-4)] * [(x-2)(x-3)]
= [x^2 - 5x +4] * [[x^2 - 5x + 6]
= (x^2 - 5x)^2 + (4 + 6)* (x^2 - 5x) + 4 * 6
= (x^2 - 5x)^2 + 10(x^2 - 5x) + 24
= x^2 - 10x^3 + 25x^2 + 10x^2 - 50x + 24
= x^4 - 10x^3 + 35x^2 - 50x + 24
(x-1)(x-2)(x-3)(x-4)-120 谁能告诉我过程的答案,化简的,
(x-1)(x-2)(x-3)(x-4)-120
=[(X-1)(X-4)][(X-2)(X-3)]-120
=[(X²-5X)+4][(X²-5X)+6]-120
=(X²-5X)²+10(X²-5X)+24-120
=(X²-5X)²+10(X²-5X)-96
=(X²-5X-6)(X²-5X+16)
=(X-6)(X+1)(X²-5X+16)
y=(x-1)(x-2)^2(x-3)^3(x-4)^4求导
lny=ln(x-1)+2ln(x-2)+3ln(x-3)+4ln(x-4)
y'/y=1/(x-1)+ 2/(x-2) +3/(x-3) +4/(x-4)
∴y'=(x-2)²(x-3)^3(x-4)^4 +2(x-1)(x-2)(x-3)^3(x-4)^4 +3(x-1)(x-2)^2(x-3)^2(x-4)^4
+4(x-1)(x-2)²(x-3)³(x-4)³