(2x-y²)-(2x-y)-(2x-y)+x(2x+y)其中x=4,y=2?(计算:(2x²+y²)(2x²-y²))
更新时间:2021-08-01 02:18:15 • 作者:SAMUEL •阅读 5526
- 计算:(2x²+y²)(2x²-y²)
- (2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)],其中 x=-1,y=2
- 分式加减2x²/(x-y)²+x²-4xy/(y-x)²-x²-2y²/x²-2xy+y²
- (x+y)*(x²/(x²-y²))+y²/(x-y)-(2x²y-2xy²)/(x²-2xy+²y)
计算:(2x²+y²)(2x²-y²)
平方差公式 运用
=(2x²)²-(y²)²=4x∧4-y∧4
(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)],其中 x=-1,y=2
-6
分式加减2x²/(x-y)²+x²-4xy/(y-x)²-x²-2y²/x²-2xy+y²
2x²/(x-y)²+x²-4xy/(y-x)²-x²-2y²/x²-2xy+y²
=(2x²+x²-4xy-x²+2y²)/(x-y)²;
=(2x²-4xy+2y²)/(x-y)²
=2(x-y)²/(x-y)²;
=2;
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(x+y)*(x²/(x²-y²))+y²/(x-y)-(2x²y-2xy²)/(x²-2xy+²y)
在x≠y的情况下
原式=( x + y ) * ( x² / ( x- y)(x+y)) + y² / ( x - y ) -2xy ( x- y) / ( x-y)²
=x² / ( x- y) + y² / ( x - y ) - 2xy/ ( x-y)
=x² / ( x- y) + y² / ( x - y ) - 2xy/ ( x-y)
=(x²- 2xy+ y² ) / ( x - y )
=( x-y)² / ( x - y )
=x-y