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sec[arcsin(1392/1417)],怎么解答 secarctanx等于多少

sec[arcsin(1392/1417)],怎么解答secarctanx等于多少

sec(arcsin(3/4))怎么解答

解:令arcsin(3/4)=α,

则,sinα=3/4.

cosα=√(1-sin^2α)=√7/4,

secα=1/cosα,

=1/(√7/4),

=4√7/7,

∴sec(arcsin(3/4)=4√7/7.