sql查询出所有重复数据 sql筛选出重复数据

查询重复数据,方法如下:select * from [表A] where id in (select id from [表A] group by id having count(id) >1 )

如果后面地址都是一样,那么还可以这样 select * from 表A where name in (select distinct name from 表B ) 或者用Group by 也行

SELECT 某一列, COUNT( 某一列 ) FROM 表 GROUP BY 某一列 HAVING COUNT( 某一列 ) 〉1 这样查询出来的结果, 就是 有重复, 而且 重复的数量.

select distinc 列名 from 表名 加上此关键字可以将重复的数据以一条显示出来!

关键字distinct 去除重复,如下列sql,去除test相同的记录;1. select distinct test from table2. 如果是要删除表中存在的重复记录,那就逻辑处理,如下:3. select test from table group by test having count(test)>14. 先查询存在重复的数据,后面根据条件删除

select id, name, memo from A where id in (select id from A group by id having count(1) >= 2) 以上回答你满意么?

1查询 abcd相同的记录:select * from F where a=b and b=c and c=d2查询有重复数据的记录 select * from F group by a,b,c,d having count(*)>13取出数据过滤到重复的数据 select distinct a,b,c,d from f

select * from table1 a where a.rowid!=(select max(rowid) from table1 b where a.第一个字段=b.第一个字段 and a.第二个字段=b.第二个字段); 后边的a.id=b.id 可以列出多个来,如果找完全相同的两条记录则是a的每个字段都与b的每个字段相等

select count(name) c,name from student where c>1 不知道sql对不对 思路应该没问题 应该会报 不是分组 的错误吧调一调 select count(name) c,max(name) from student group by name having c>1 ??自己调一调吧,应该差不多

假设该表id作为pk,只保留一条shopname不重复数据 delete from shop where id not in(select min(id) from shop group by shopname) 效率不是很高,但是通用性比较强