x^3+x^2+4y^2-8y^3因式分解？(因式分解x⁴-x³-3x²+x+2)
更新时间：2021-07-29 19:12:43 • 作者：MARIANNE •阅读 5320
因式分解x⁴-x³-3x²+x+2
=x^3 (x-1) + (x-1)(-3x-2)
= (x-1)(x^3 - 3x - 2)
= (x-1)(x-1)(x^2 +x +2)
因式分解：(x²-3）²-x(x²-3）-2x²
(x²-3）²-x(x²-3）-2x²
=[(x^2-3)-2x][(x^2-3)+x]
=(x^2-2x-3)(x^2+x-3)
=(x-3)(x+1)(x^2+x-3)
分解因式 x³-3x+2
x³-3x+2
=(x³-1)-3x+3
=(x-1)(x^2+x+1)-3(x-1)
=(x-1)(x^2+x+1-3)
=(x-1)(x^2+x-2)
=(x-1)^2(x+2)
x的3次方-3X+2 怎么因式分解
x^3-3x+2=x^3-3x+3-1=(x^3-1)-3(x-1)=(x-1)(x^2+x+1)-3(x-1)=(X-1)(x^2+x-2)=(x-1)^2(x+2)