因式分解3(x-y)³-(x-y)²=(ⅹ-y)²[3(ⅹ-y)-1]这是为什么?(分解因式:x³y²(x-y)³-x²y³(y-
更新时间:2021-07-17 11:11:13 • 作者:JANICE •阅读 1698
分解因式:x³y²(x-y)³-x²y³(y-x)³
原式=x2y2(x(x-y)3--y(y-x)3 )
=x2y2(x(x-y)3+y(x-y)3)
=x2y2(x+y)(x-y)3
其实(x-y)3还可以分解,但是一般用不着了,看具体题目的
亲、满意请采纳哦
分解因式x²-y²-x-y,谢谢
平方差公式 x²-y²=(x+y)*(x-y) x²-y²-x-y= (x+y)*(x-y)-(x+y)
提取x+y 原式=(x+y)(x-y-1)
因式分解(x²+y²)²-x²y²
(x²+y²)²-x²y²
=(x²+y²+xy)(x²+y²-xy)
因式分解x³-x²y-xy²-3y
解析:
x³-x²y-xy²+y³
=(x³+y³)-(x²y+xy²)
=(x+y)(x²-xy+y²)-xy(x+y)
=(x+y)(x²-2xy+y²)
=(x+y)(x-y)²