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y=ln(2x²➕x➖10)由那些简单函数组成?

y=ln(2x²+x - 10)是由那些简单函数组成

y=ln(2x²➕x➖10)由那些简单函数组成?

对数函数,二次函数

求导:y=ln[x+(a²+x²)½]

y'=ln[x+(a²+x²)½]'=1/[x+(a²+x²)½]*知[x+(a²+x²)½]'=[x+(a²+x²)½]'/[x+(a²+x²)½]=[1+((a²+x²)½)']/[x+(a²+x²)½]=[1+(1/2(a²+x²)^道(½-1)(a^2+x^2)']/[x+(a²+x²)½]=[1+1/2(a²+x²)^(-½)*2x]/[x+(a²+x²)½]=[1+(a²+x²)^(-½)x]/[x+(a²+x²)½]

分解因式:xy³ - 2x²y²+x³y

xy³-2x²y²+x³y=xy(y^2-2xy+x^2)=xy(x-y)^2

﹙ - 2x³Y²﹢3X²Y²﹚÷﹙﹣½X²Y²﹚

﹙-2x³Y²﹢3X²Y²﹚÷﹙﹣½X²Y²﹚=(-2x³y²)÷(-1/2x²y²)+(3x²y²)÷(-1/2x²y²)=4x-6

1/2x²y·()=2x³y - x²y²

=(4x²y)/(-2x²y)-(x³y³)/(-2x²y)=-2+(xy²/2)=[(xy²)/2]-2,请采纳,谢谢.

求y=ln(a² - x²)的导数

y=ln(a²-x²) y'=[1/(a²-x²)]·(a²-x²)' ∴y'=-2x/(a²-x²) 即y'=2x/(x²-a²).

(x十2y)²(x - y)十4y²(x十2y) - 4x²y

(X+2Y)²(X-Y)+4Y²(X+2Y)-4X²Y=(X+2Y)[(X+2Y)(X-Y)+4Y²]-4X²Y=(X+2Y)(X²-XY+2XY-2Y²+4Y²)-4X²Y=(X+2Y)(X²+XY+2Y²)-4X²Y=X³+X²Y+2XY²+2X²Y+2XY²+4Y³-4X²Y=X³-X²Y+4XY²+4Y³=X²(X-Y)+4Y²(X+Y)

(8xy - x²+y²) - (x² - y²+8xy)

(8xy-x²+y²)-(x²-y²+8xy) = 8xy - x^2 + y^2 - x^2 + y^2 - 8xy = -2x^2 + 2y^2

∫∫(y²/x²)dσ,其中D由曲线x²+y²=2x所围成的平面区域.

∵d={(x,y)|0≤x≤1,x≤y≤2x} ∴ ∫∫ d xydxdy= ∫ 10 dx ∫ 2x x xydy= ∫ 10 x(2x2?1 2 x2)dx=3 2 ∫ 10 x3dx=3 8

y²=(x²)² - 2lny的隐函数的导数

y²=(x²)²-2lnyy²+2lny=x^42yy'+(2/y)y'=4x³(y+1/y)y'=2x³(y²+1)y'=2x³yy'=2x³y/(y²+1)