lingo错误11的改正 lingo出现错误代码11
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求助!!!!!lingo报错代码11MODEL:SETS:quarters/1,2,3,4/:dem,rp,op,inv; ENDSETS min=@sum(quarters:400*rp+450*op+20*inv); @for(quarters:rp@for(quarters(i)|i#gt#1:inv(i)=inv(i-1)+rp(i)+op(i)-.
lingo程序总是报错11怎么办sets: hang/1..3/:x; lie/1..3/; links(hang,lie):c; endsets data: c=1 -2 3 -4 1 2 -2 0 1; enddata max=3*x(1)-x(2)-x(3); @for(hang(i):x(i)*c(1,i)<=11); !@for(hang(i):x(i)*c(2,i)>=3); !@for(hang(i).
lingo运行编好程序时出现错误11,下面是公式,求教怎么改MODEL: title locate problem; sets: demand/1..6/:a,b,d; supply/1..2/:x,y,e; link(demand,. d=3,5,4,7,6,11;e=20,20; enddata init: x,y=5,1,2,7; endinit [OBJ] min=@sum(link(i,j):c(i,j.
lingo错误11,这是哪有问题啊min目标函数那一行少了分号.还有,你一道题解不出来..
lingo error 11,求大神帮忙看错在哪你这里有很多全角的空格 所以出问题 model: min=1200*(x1+x2)+1500*(x3+x4); x1+x2>=30; x1+x2>=35; x1+x3+x4>=20; x2+x3+x4>=20; x1+x2+x3+x4>=40; x1+x2+x4>=30; .
lindo程序修改,第一句有error code 11,怎么办?帮忙修改,然.代码如下: max 5x1+9x2+6x3+3x4+2x5 st x1+x2<=1<br>x3+x4<=1<br>x5-x2>=0 4x1+6x2+5x3+4x4+3x5<=10<br>end 结果: LP OPTIMUM FOUND AT STEP 3 OBJECTIVE FUNCTION VALUE 1) 12.20000 VARIABLE VALUE REDUCED COST X1 0.000000 0.000000 X2 1.000000 0.000000 X3 0.200000 0.000000 X4 0.000000 1.800000 X5 1.000000 0.000000 ROW SLACK OR SURPLUS DUAL PRICES 2) 0.000000 0.200000 3) 0.800000 0.000000 .
急!!!lingo错误代码11model: max=175*x1+300*x2+120*x3+2.1*x4+1.8*x5+400*x6+2*x7; x1+x2+x3+1.5*x6<=100;<br>400*x6+3*x7<=15000;<br>50*x1+75*x2+40*x3+x4+50+0.3*x7<=4000;<br>20*x1+35*x2+10*x3+x5+100+0.6*x7<=3500;<br>x6<=32;<br>x7<=3000;<br>@gin(x1); @gin(x2); @gin(x3); @gin(x4); @gin(x5); @gin(x6); @gin(x7); end 运行结果: Global optimal solution found. Objective value: 31396.00 Objective bound: 31396.00 Infeasibilities: 0.000000 Extended .
lingo error code:11 请高手指点sets: plan/1..5/:x,t1,t2,invest,fee,sfee,eff1,eff2,waste,wl; endsets data: invest=0 20 0 10 50; fee=5 7 8 8 12; sfee=3 5 8 10 14; eff1=1000 1500 1200 1600 1600; eff2=800 1400 1000 1300 1200; waste=2 2 3 3 3; wl=30 30 50 50 50; . *t2(2)*eff2(2)=2000; 0.97*x(3)*t1(3)*eff1(3)+0.97*x(4)*t1(4)*eff1(4)+0.97*x(5)*t1(5)*eff1(5)=10000; 0.97*x(3)*t2(3)*eff2(3)+0.97*x(4)*t2(4)*eff2(4)+0.97*x(5)*t2(5)*eff2(5)=8000; @for(plan(i):t1(i)+t2(i)<=8000); 问题不少 细微错误.
请高手帮我看看lingo编程的问题,从第一个约束条件就显示.问题在于: (1)语句尾的分号的问题,有些分号是中文状态的,必须全修改为英文状态的才行;这改起来不难,“编辑”-“替换”即可; (2)末尾“end”不必要; 另外,你的代码不简练.
帮我看看这段lingo代码,我不明白为什么一直出现error code.是圆括号()不是花括号{} MODEL: SETS: QUARTERS/1,2,3,4/:DEM,RP,OP,INV; ENDSETS MIN=@sum(QUARTERS:400*RP+450*OP+20*INV); @FOR(QUARTERS(I):RP(I)<40);<br> @FOR(QUARTERS(I)|I#GT#1: INV(I)=INV(I-1)+RP(I)+OP(I)-DEM(I)); INV(1)=10+RP(1)+OP(1)-DEM(1); DATA: DEM=40,60,75,25; ENDDATA END
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