从键盘输入一个整数 c语言从键盘输入数据

#include<stdio.h> void showbit(int n) { if(n>1){ showbit(n/2); printf(" "); } printf("%d. printf("input a num:"); scanf("%d",&a); showbit(a); printf("\n"); showoct(a); .

#include<bits/stdc++.h>using namespace std;int main(){ float s; int a,b,c; int n; cin>>n; a=n/100; b=n%100/10; c=n%10; s=(a+b)*c/2.0; cout<<s; return 0;}

原发布者:血战长空wlg 题目:数制转换问题1.需求分析将十进制数N转换成八进制数. 2)功能:从键盘输入任意一个非负十进制整数,输出与其等值的八进制数;若输入.

#include ＂stdio.h＂ main() { int numberOfPositive = 0; int numberOfNegative = 0; int numberOfOdd = 0; int numberOfEven = 0; int currentNumber = 0; while (1) { printf(＂.

这是我以前写的,今天不想砍代码,就发这个了#include<stdio.h>#include<stdlib.h>#. while(exit!='y'&&exit!='Y'); }/*从键盘输入一系列整数,当输入值为0时,停止输入,.

#include <iostream> using namespace std; class stack { public: stack(int n) : base(new int[n]), sp(base), size(0), capacity(n) { } int push(int n) { *sp++ = n; ++size; return n.