C++控制台计算个人所得税？ 计算个人所得税c语言编程
用C#控台应用程序编写一个计算个人所得税的程序，具体要求如下，谢谢
decimal CalTax(decimal totalIncome)
{
decimal tax, income;
if(totalIncome <= 1600)
tax = 0;
else
{
income = totalIncome - 1600;
if(income <= 500)
tax = income * 0.05;
else
if(income <= 2000)
tax = 500 * 0.05 + (income - 500) * 0.1;
else
if(income <= 5000)
tax = 500 * 0.05 + 1500 * 0.1 + (income - 2000)* 0.15;
else
if(income <= 20000)
tax = 500 * 0.05 + 1500 * 0.1 + 3000 * 0.15 + (income - 5000)* 0.2;
else
//以下类似......
}
return tax;
}
我百度到的……
C语言计算个人所得税 编程
#include "stdio.h"
int main(void){
double s,rs,rat;
printf("Enter your number should get salary...\ns=");
scanf("%lf",&s);
if(rs=s-2000,rs<500)
rat=0.05;
else if(rs>=500 && rs<2000)
rat=0.1;
else if(rs>=2000 && rs<5000)
rat=0.15;
else if(rs>=5000 && rs<20000)
rat=0.2;
else if(rs>=20000 && rs<40000)
rat=0.25;
else if(rs>=40000 && rs<60000)
rat=0.3;
else if(rs>=60000 && rs<80000)
rat=0.35;
else if(rs>=80000 && rs<100000)
rat=0.4;
else if(rs>=100000)
rat=0.45;
printf("Your SGS: %.2f\tTAX: %.2f\tAGS:%.2f\n",s,rat*rs,s-rat*rs);
return 0;
}
编写计算个人所得税的c语言源程序代码及流程图
#include
#define TAXBASE 2000
typedef struct{
long base;
long limit;
double taxrate;
}TAXTABLE;
TAXTABLE TaxTable[] = {\
{0, 500, 0.05},\
{500, 2000, 0.10},\
{2000, 5000, 0.15},\
{5000, 20000, 0.20},\
{20000, 40000, 0.25},\
{40000, 60000, 0.30},\
{60000, 80000, 0.35},\
{80000, 100000, 0.40},\
{100000,1e10, 0.45},\
};
double CaculateTax(long profit)
{
int i;
double tax = 0.0;
profit -= TAXBASE;
for(i=0; i< sizeof(TaxTable)/sizeof(TAXTABLE); i++)
{
if( profit > TaxTable[i].base )
{
if( profit > TaxTable[i].limit )
{
tax += (TaxTable[i].limit - TaxTable[i].base) * TaxTable[i].taxrate;
}
else
{
tax += (profit - TaxTable[i].base) * TaxTable[i].taxrate;
}
profit -= TaxTable[i].limit;
printf("Base%d:%6ld Limit%d:%6ld Tax:%12.2f Leave:%6ld\n",i,TaxTable[i].base,i,\
TaxTable[i].limit, tax, (profit)>0 ? profit : 0);
}
}
return tax;
}
int main(void)
{
long profit;
double tax;
printf("Please enter your profit:");
scanf("%ld",&profit);
tax = CaculateTax(profit);
printf("Tax is: %12.2f\n",tax);
return 0;
}
C++一个算个人所得税的程序
#include
int main(void)
{
int x;
double y;
printf("请输入你的工资薪金总和：");
scanf("%d",&x);
if(x<=1600)
{
printf("您不需要交纳所得税");
}
else
if(x>1600&&x<=2100)
{
y=(x-1600)*0.05;
printf("%lf",y);
}
else
if(x>2100&&x<=3600)
{
y=(x-2100)*0.1+25;
printf("%lf",y);
}
else
if(x>3600&&x<=6600)
{
y=(x-3600)*0.15+150+25;
printf("%lf",y);
}
else
if(x>6600&&x<=21600)
{
y=(x-6600)*0.2+450+200+25;
printf("%lf",y);
}
else
if(x>21600&&x<=41600)
{
y=(x-21600)*0.25+3000+450+200+25;
printf("%lf",y);
}
else
if(x>41600&&x<=61600)
{
y=(x-41600)*0.3+5000+3000+450+200+25;
printf("%lf",y);
}
else
if(x>61600&&x<=81600)
{
y=(x-61600)*0.35+6000+5000+3000+450+200+25;
printf("%lf",y);
}
else
if(x>81600&&x<=101600)
{
y=(x-81600)*0.4+7000+6000+5000+3000+450+200+25;
printf("%lf",y);
}
else
{y=(x-101600)*0.45+8000+7000+6000+5000+3000+450+200+25;
printf("%lf",y);
}
return 0;
}
现在就可以了，我把x定义为int类型